Đỗ Nguyễn Đức Lâm
Giới thiệu về bản thân
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x=(-0,25)^2=\(\dfrac{-1}{4}^2\)=\(\dfrac{1}{16}\)
a) \(\dfrac{51}{20}\)*\(\dfrac{25}{36}\)=\(\dfrac{85}{48}\)
b) \(\dfrac{-22}{25}\)+\(\dfrac{520}{175}\)=\(\dfrac{366}{175}\)
Số khóm hoa trồng được theo hai cạnh chiều dài là:
2.(5,5 : 0,25 + 1) = 46 (khóm hoa)
Số khóm hoa trồng được theo hai cạnh chiều rộng là:
2.(3,75 : 0,25 + 1) = 32 (khóm hoa)
Vậy số khóm hoa cần trồng là:
46 + 32 – 4 = 74 (khóm hoa)
a) \(\dfrac{4}{5}\)⋮x=\(\dfrac{3}{4}\)-\(\dfrac{1}{5}\) \(\dfrac{4}{5}\)⋮x=\(\dfrac{11}{20}\) x=\(\dfrac{4}{5}\)⋮\(\dfrac{11}{20}\) x=\(\dfrac{16}{11}\) b) x+\(\dfrac{1}{2}\)=1-x x+\(\dfrac{1}{2}\)=0 x=0-\(\dfrac{1}{2}\)=-\(\dfrac{1}{2}\)
a \(\dfrac{2}{3}\)*\(\dfrac{5}{4}\)-\(\dfrac{3}{4}\)=\(\dfrac{2}{3}\)*\(\dfrac{1}{2}\)=\(\dfrac{1}{3}\) b 2*\(\dfrac{9}{4}\)-\(\dfrac{7}{2}\)=\(\dfrac{9}{2}\)-\(\dfrac{7}{2}\)=1 c -\(\dfrac{3}{4}\)*\(\dfrac{68}{13}\)-\(\dfrac{3}{4}\)*\(\dfrac{36}{13}\)=\(\dfrac{3}{4}\)*\(\dfrac{-68}{13}\)-\(\dfrac{3}{4}\)*\(\dfrac{36}{13}\)=\(\dfrac{3}{4}\)* (-\(\dfrac{68}{13}\) -\(\dfrac{36}{13}\))=\(\dfrac{3}{4}\)*(-8)=-6
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